Integrand size = 18, antiderivative size = 51 \[ \int \frac {x^2}{\log \left (c \left (d+e x^3\right )^p\right )} \, dx=\frac {\left (d+e x^3\right ) \left (c \left (d+e x^3\right )^p\right )^{-1/p} \operatorname {ExpIntegralEi}\left (\frac {\log \left (c \left (d+e x^3\right )^p\right )}{p}\right )}{3 e p} \]
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Time = 0.04 (sec) , antiderivative size = 51, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.222, Rules used = {2504, 2436, 2337, 2209} \[ \int \frac {x^2}{\log \left (c \left (d+e x^3\right )^p\right )} \, dx=\frac {\left (d+e x^3\right ) \left (c \left (d+e x^3\right )^p\right )^{-1/p} \operatorname {ExpIntegralEi}\left (\frac {\log \left (c \left (e x^3+d\right )^p\right )}{p}\right )}{3 e p} \]
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Rule 2209
Rule 2337
Rule 2436
Rule 2504
Rubi steps \begin{align*} \text {integral}& = \frac {1}{3} \text {Subst}\left (\int \frac {1}{\log \left (c (d+e x)^p\right )} \, dx,x,x^3\right ) \\ & = \frac {\text {Subst}\left (\int \frac {1}{\log \left (c x^p\right )} \, dx,x,d+e x^3\right )}{3 e} \\ & = \frac {\left (\left (d+e x^3\right ) \left (c \left (d+e x^3\right )^p\right )^{-1/p}\right ) \text {Subst}\left (\int \frac {e^{\frac {x}{p}}}{x} \, dx,x,\log \left (c \left (d+e x^3\right )^p\right )\right )}{3 e p} \\ & = \frac {\left (d+e x^3\right ) \left (c \left (d+e x^3\right )^p\right )^{-1/p} \text {Ei}\left (\frac {\log \left (c \left (d+e x^3\right )^p\right )}{p}\right )}{3 e p} \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 51, normalized size of antiderivative = 1.00 \[ \int \frac {x^2}{\log \left (c \left (d+e x^3\right )^p\right )} \, dx=\frac {\left (d+e x^3\right ) \left (c \left (d+e x^3\right )^p\right )^{-1/p} \operatorname {ExpIntegralEi}\left (\frac {\log \left (c \left (d+e x^3\right )^p\right )}{p}\right )}{3 e p} \]
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 1.79 (sec) , antiderivative size = 272, normalized size of antiderivative = 5.33
method | result | size |
risch | \(-\frac {\left (e \,x^{3}+d \right ) {\left (\left (e \,x^{3}+d \right )^{p}\right )}^{-\frac {1}{p}} c^{-\frac {1}{p}} {\mathrm e}^{\frac {i \pi \,\operatorname {csgn}\left (i c \left (e \,x^{3}+d \right )^{p}\right ) \left (-\operatorname {csgn}\left (i c \left (e \,x^{3}+d \right )^{p}\right )+\operatorname {csgn}\left (i c \right )\right ) \left (-\operatorname {csgn}\left (i c \left (e \,x^{3}+d \right )^{p}\right )+\operatorname {csgn}\left (i \left (e \,x^{3}+d \right )^{p}\right )\right )}{2 p}} \operatorname {Ei}_{1}\left (-\ln \left (e \,x^{3}+d \right )-\frac {i \pi \,\operatorname {csgn}\left (i \left (e \,x^{3}+d \right )^{p}\right ) {\operatorname {csgn}\left (i c \left (e \,x^{3}+d \right )^{p}\right )}^{2}-i \pi \,\operatorname {csgn}\left (i \left (e \,x^{3}+d \right )^{p}\right ) \operatorname {csgn}\left (i c \left (e \,x^{3}+d \right )^{p}\right ) \operatorname {csgn}\left (i c \right )-i \pi {\operatorname {csgn}\left (i c \left (e \,x^{3}+d \right )^{p}\right )}^{3}+i \pi {\operatorname {csgn}\left (i c \left (e \,x^{3}+d \right )^{p}\right )}^{2} \operatorname {csgn}\left (i c \right )+2 \ln \left (c \right )+2 \ln \left (\left (e \,x^{3}+d \right )^{p}\right )-2 p \ln \left (e \,x^{3}+d \right )}{2 p}\right )}{3 e p}\) | \(272\) |
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Time = 0.31 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.57 \[ \int \frac {x^2}{\log \left (c \left (d+e x^3\right )^p\right )} \, dx=\frac {\operatorname {log\_integral}\left ({\left (e x^{3} + d\right )} c^{\left (\frac {1}{p}\right )}\right )}{3 \, c^{\left (\frac {1}{p}\right )} e p} \]
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\[ \int \frac {x^2}{\log \left (c \left (d+e x^3\right )^p\right )} \, dx=\int \frac {x^{2}}{\log {\left (c \left (d + e x^{3}\right )^{p} \right )}}\, dx \]
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\[ \int \frac {x^2}{\log \left (c \left (d+e x^3\right )^p\right )} \, dx=\int { \frac {x^{2}}{\log \left ({\left (e x^{3} + d\right )}^{p} c\right )} \,d x } \]
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Time = 0.32 (sec) , antiderivative size = 31, normalized size of antiderivative = 0.61 \[ \int \frac {x^2}{\log \left (c \left (d+e x^3\right )^p\right )} \, dx=\frac {{\rm Ei}\left (\frac {\log \left (c\right )}{p} + \log \left (e x^{3} + d\right )\right )}{3 \, c^{\left (\frac {1}{p}\right )} e p} \]
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Timed out. \[ \int \frac {x^2}{\log \left (c \left (d+e x^3\right )^p\right )} \, dx=\int \frac {x^2}{\ln \left (c\,{\left (e\,x^3+d\right )}^p\right )} \,d x \]
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